SOLUTION: Graph y=(1/3)^x. Identify the domain, asymptote, and range. Did I do this right? x=3 -2 -1 0 1 2 3 y=27 9 3 1 1/3 1/9 1/27 Domain=all real #s asymptote=y=
SOLUTION: For the Function: y=1/x-1 Give the y values for x=2,-1,0,1,2,3 Use the points to draw a smooth curve graph. Thanks you!!!
![If | x | < 1 and | y | < 1, then the sum of infinity of the series (x + y) + (x^2 + xy + y^2) + (x^3 + x^2y + xy^2 + y^3) + ..... to ∞ is If | x | < 1 and | y | < 1, then the sum of infinity of the series (x + y) + (x^2 + xy + y^2) + (x^3 + x^2y + xy^2 + y^3) + ..... to ∞ is](https://haygot.s3.amazonaws.com/questions/1985539_1255658_ans_a4da1a92ffd74b5895a27a49ebadfa89.jpeg)
If | x | < 1 and | y | < 1, then the sum of infinity of the series (x + y) + (x^2 + xy + y^2) + (x^3 + x^2y + xy^2 + y^3) + ..... to ∞ is
![Plot the Shape of My Heart. How two simple functions form a… | by Slawomir Chodnicki | Towards Data Science Plot the Shape of My Heart. How two simple functions form a… | by Slawomir Chodnicki | Towards Data Science](https://miro.medium.com/max/1200/1*bOYvdJ1cZ5qNTwtwTP5luw.png)